3.744 \(\int \frac {\sqrt [3]{a+b x^2}}{(c x)^{23/3}} \, dx\)

Optimal. Leaf size=85 \[ -\frac {27 \left (a+b x^2\right )^{10/3}}{280 a^3 c (c x)^{20/3}}+\frac {9 \left (a+b x^2\right )^{7/3}}{28 a^2 c (c x)^{20/3}}-\frac {3 \left (a+b x^2\right )^{4/3}}{8 a c (c x)^{20/3}} \]

[Out]

-3/8*(b*x^2+a)^(4/3)/a/c/(c*x)^(20/3)+9/28*(b*x^2+a)^(7/3)/a^2/c/(c*x)^(20/3)-27/280*(b*x^2+a)^(10/3)/a^3/c/(c
*x)^(20/3)

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Rubi [A]  time = 0.02, antiderivative size = 85, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {273, 264} \[ -\frac {27 \left (a+b x^2\right )^{10/3}}{280 a^3 c (c x)^{20/3}}+\frac {9 \left (a+b x^2\right )^{7/3}}{28 a^2 c (c x)^{20/3}}-\frac {3 \left (a+b x^2\right )^{4/3}}{8 a c (c x)^{20/3}} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x^2)^(1/3)/(c*x)^(23/3),x]

[Out]

(-3*(a + b*x^2)^(4/3))/(8*a*c*(c*x)^(20/3)) + (9*(a + b*x^2)^(7/3))/(28*a^2*c*(c*x)^(20/3)) - (27*(a + b*x^2)^
(10/3))/(280*a^3*c*(c*x)^(20/3))

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 273

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(
a*c*n*(p + 1)), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; FreeQ[
{a, b, c, m, n, p}, x] && ILtQ[Simplify[(m + 1)/n + p + 1], 0] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {\sqrt [3]{a+b x^2}}{(c x)^{23/3}} \, dx &=-\frac {3 \left (a+b x^2\right )^{4/3}}{8 a c (c x)^{20/3}}-\frac {3 \int \frac {\left (a+b x^2\right )^{4/3}}{(c x)^{23/3}} \, dx}{2 a}\\ &=-\frac {3 \left (a+b x^2\right )^{4/3}}{8 a c (c x)^{20/3}}+\frac {9 \left (a+b x^2\right )^{7/3}}{28 a^2 c (c x)^{20/3}}+\frac {9 \int \frac {\left (a+b x^2\right )^{7/3}}{(c x)^{23/3}} \, dx}{14 a^2}\\ &=-\frac {3 \left (a+b x^2\right )^{4/3}}{8 a c (c x)^{20/3}}+\frac {9 \left (a+b x^2\right )^{7/3}}{28 a^2 c (c x)^{20/3}}-\frac {27 \left (a+b x^2\right )^{10/3}}{280 a^3 c (c x)^{20/3}}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 52, normalized size = 0.61 \[ -\frac {3 \sqrt [3]{c x} \left (a+b x^2\right )^{4/3} \left (14 a^2-12 a b x^2+9 b^2 x^4\right )}{280 a^3 c^8 x^7} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^2)^(1/3)/(c*x)^(23/3),x]

[Out]

(-3*(c*x)^(1/3)*(a + b*x^2)^(4/3)*(14*a^2 - 12*a*b*x^2 + 9*b^2*x^4))/(280*a^3*c^8*x^7)

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fricas [A]  time = 1.25, size = 57, normalized size = 0.67 \[ -\frac {3 \, {\left (9 \, b^{3} x^{6} - 3 \, a b^{2} x^{4} + 2 \, a^{2} b x^{2} + 14 \, a^{3}\right )} {\left (b x^{2} + a\right )}^{\frac {1}{3}} \left (c x\right )^{\frac {1}{3}}}{280 \, a^{3} c^{8} x^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^(1/3)/(c*x)^(23/3),x, algorithm="fricas")

[Out]

-3/280*(9*b^3*x^6 - 3*a*b^2*x^4 + 2*a^2*b*x^2 + 14*a^3)*(b*x^2 + a)^(1/3)*(c*x)^(1/3)/(a^3*c^8*x^7)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{2} + a\right )}^{\frac {1}{3}}}{\left (c x\right )^{\frac {23}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^(1/3)/(c*x)^(23/3),x, algorithm="giac")

[Out]

integrate((b*x^2 + a)^(1/3)/(c*x)^(23/3), x)

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maple [A]  time = 0.01, size = 42, normalized size = 0.49 \[ -\frac {3 \left (b \,x^{2}+a \right )^{\frac {4}{3}} \left (9 b^{2} x^{4}-12 a b \,x^{2}+14 a^{2}\right ) x}{280 \left (c x \right )^{\frac {23}{3}} a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^2+a)^(1/3)/(c*x)^(23/3),x)

[Out]

-3/280*x*(b*x^2+a)^(4/3)*(9*b^2*x^4-12*a*b*x^2+14*a^2)/a^3/(c*x)^(23/3)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{2} + a\right )}^{\frac {1}{3}}}{\left (c x\right )^{\frac {23}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^(1/3)/(c*x)^(23/3),x, algorithm="maxima")

[Out]

integrate((b*x^2 + a)^(1/3)/(c*x)^(23/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (b\,x^2+a\right )}^{1/3}}{{\left (c\,x\right )}^{23/3}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^2)^(1/3)/(c*x)^(23/3),x)

[Out]

int((a + b*x^2)^(1/3)/(c*x)^(23/3), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**2+a)**(1/3)/(c*x)**(23/3),x)

[Out]

Timed out

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